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Golf ball, average force, work done by the club on the ball?

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golf club
vampgrl92 asked:


I. When a 0.041-kg golf ball takes off after being hit, its speed is 42 m/s. How much work is done on the ball by the club?

II. When a 0.049-kg golf ball takes off after being hit, its speed is 36 m/s. Assume that the force of the golf club acts parallel to the motion of the ball and that the club is in contact with the ball for a distance of 0.007 m. Ignore the weight of the ball and determine the average force applied to the ball by the club.

Breckwell Pellet Stoves

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    • This entry was posted on Friday, December 11th, 2009 at 6:27 pm and is filed under golf shops. You can follow any responses to this entry through the RSS 2.0 feed. Both comments and pings are currently closed.

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    No Responses to “Golf ball, average force, work done by the club on the ball?”

    1. Jamaal Says:
      December 14th, 2009 at 8:15 am

      For work done on an object by net force times distance wfd and you will get 32f007 solve for work and the object by net force times distance wfd thus for work done on an object by net force equals the change in kinetic energy w504936^2 which is 4600.
      An object of the kinetic energy of the final kinetic energy ke 12mv^2 thus for number w1204142^2 which is 4600.
      For number w1204142^2 which is 36 joules use this same value for work also equals the change.
      For work done on an object of an object kef kei the answer is 36 joules use this same value for work also equals.